k^2-5.2k+1=0

Solution for k^2-5.2k+1=0 equation:

k^2-5.2k+1=0

a = 1; b = -5.2; c = +1;
Δ = b2-4ac
Δ = -5.22-4·1·1
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.2)-\sqrt{23.04}}{2*1}=\frac{5.2-\sqrt{23.04}}{2}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.2)+\sqrt{23.04}}{2*1}=\frac{5.2+\sqrt{23.04}}{2}
$